# Complex Gate MCQs & Quiz Online PDF Book Download

Complex gate MCQs, complex gate quiz answers to learn online digital electronics courses. Cmos logic gates circuits multiple choice questions (MCQs), complex gate quiz questions and answers for online masters degree. Cmos nand gate, basic cmos gate structure representation, cmos exclusive or gate, complex gate test prep for engineering certifications.

Learn cmos logic gates circuits test MCQs: by de morgan's law y=bar(a)+bar(b+cd) is equals to, with choices bar(a)bar(b+cd), bar(a)+bar(b)(cd), bar(a)+bar(b)bar(cd), and bar(a)bar(b)bar(cd) for online masters degree. Practice assessment test for scholarships, online learning complex gate quiz questions for competitive assessment in engineering majors.

## MCQ on Complex Gate Quiz Book Download

MCQ: By De Morgan's Law Y=bar(A)+bar(B+CD) is equals to

- bar(A)bar(B+CD)
- bar(A)+bar(B)(CD)
- bar(A)+bar(B)bar(CD)
- bar(A)bar(B)bar(CD)

C

MCQ: By DE Morgan's Law Y=bar(A(B+CD)) is equals to

- bar(A)bar(B+CD)
- bar(A)+bar(B+CD)
- A+bar(B+CD)
- bar(A)+(B+CD)

B

MCQ: System in which Y is high for A input is high and simultaneously either B input is high or C and D both are high is represented as

- Y=A(B+CD)
- bar(Y)=A(B+CD)
- bar(Y)=A(2+CD)
- bar(Y)=AB+CD

A

MCQ: By De Morgan's Law Y=bar(A)+bar(B)bar(CD) is equals to

- bar(A)bar(B+CD)
- bar(A)+bar(B)(bar(C)+D)
- bar(A)+bar(B)(C+D)
- bar(A)+bar(B)(bar(C)+bar(D))

D

MCQ: System in which Y will be high if A is low or B and C are both low is represented as

- Y=A+BC
- Y=ABC
- Y=A+bar(BC)
- Y=bar(A)+bar(BC)

D