# Complex Gate MCQs Quiz Online PDF Download

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Study bachelors and masters in electrical engineering degree MCQs: by de morgan's law y=bar(a)+bar(b+cd) is equals to, for online engineering courses with choices bar(a)bar(b+cd), bar(a)+bar(b)(cd), bar(a)+bar(b)bar(cd), bar(a)bar(b)bar(cd) with online engineering degrees test preparation for communication and electronics engineering students. Free skills assessment test is for online learn complex gate quiz questions with MCQs, exam preparation questions and answers.

## MCQs on Complex Gate Quiz PDF Download

MCQ: By De Morgan's Law Y=bar(A)+bar(B+CD) is equals to

- bar(A)bar(B+CD)
- bar(A)+bar(B)(CD)
- bar(A)+bar(B)bar(CD)
- bar(A)bar(B)bar(CD)

C

MCQ: By DE Morgan's Law Y=bar(A(B+CD)) is equals to

- bar(A)bar(B+CD)
- bar(A)+bar(B+CD)
- A+bar(B+CD)
- bar(A)+(B+CD)

B

MCQ: System in which Y is high for A input is high and simultaneously either B input is high or C and D both are high is represented as

- Y=A(B+CD)
- bar(Y)=A(B+CD)
- bar(Y)=A(2+CD)
- bar(Y)=AB+CD

A

MCQ: By De Morgan's Law Y=bar(A)+bar(B)bar(CD) is equals to

- bar(A)bar(B+CD)
- bar(A)+bar(B)(bar(C)+D)
- bar(A)+bar(B)(C+D)
- bar(A)+bar(B)(bar(C)+bar(D))

D

MCQ: System in which Y will be high if A is low or B and C are both low is represented as

- Y=A+BC
- Y=ABC
- Y=A+bar(BC)
- Y=bar(A)+bar(BC)

D